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Pump Power & Efficiency

🌡️ Energy & Fluids · Hydraulic, shaft, and electrical power calculation; standard motor selection

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Ph=ρgQHP_h = \rho g Q H

Correctly calculating a pump system’s power requirement is necessary both for correct motor selection and for estimating operating costs. Power is calculated across an increasing three-stage chain:

  1. Hydraulic power (Ph): the useful power actually transferred to the fluid — calculated with the formula ρgQH.
  2. Shaft power (Ps): the power that must be applied to the shaft to compensate for the pump’s mechanical inefficiencies (seal losses, hydraulic losses) — Ps = Ph/ηpump.
  3. Electrical power (Pe): the total power drawn from the grid, also accounting for the motor’s own inefficiency — Pe = Ps/ηmotor.

Important note about head (H): this value must include not just the static height difference, but also all friction losses (hL) in the pipeline. For a correct pump selection, the head loss calculated with the Pipe Pressure Loss tool must be added to the static height.

For motor power selection, a typical 10% safety margin is added on top of the calculated requirement, then rounded up to the nearest standard motor power.

✅ Verified

This tool's calculation logic has been checked against a hand-computed numerical verification test. Test source: src/lib/calc/pompa.test.ts.

  • [4] White, Frank M.. Fluid Mechanics, 8 ed.. McGraw-Hill, 2016.

Results are for educational and preliminary-sizing purposes; final engineering design decisions must reference the relevant standards and a licensed engineer's approval.